--- In [email protected], Suyono <suyonohy@...> wrote:
>
> Hi Mark,
>
> There's no such number.
> If S is one skwiirol, then:
> S = 10^S ; S is a positive integer
> LOG10(S) = S
> No solution because LOG10(S) is always < S.
> The nearest is S = 1 and LOG10(S) = 0.
> (If S is a real number, S = 1/LN(10) = 0.4343
> and LOG10(S) = -0.3622)
>
> Bye,
> Suyono
>
> Mark wrote:
> >
> > In the spirit of "googol" I've made up my own number. I've called
it
> > a "skwiirol" which is a really good name.
> >
> > It's defined as "1 followed by a skwiirol of zeroes". The best
thing
> > about it is that it is recursive - the more you try to work out
how
> > many zeroes it actually has, the bigger it gets!
> >
> > Mark
> >
>
Re: Spoiler warning - the answer to 0, 1, 2,...
From Mark at 2006-03-01 09:05:42