Maybe I misunderstood you but when I use your formula I get: 2, 3, 6,
"infinity", -6.
I also don't feel comfortable with "infinity" as a term in a sequence. I
think that's cheating a little bit. My series has no infinite terms although
they do keep on increasing at an ever increasing rate.
I admire your tenacity. Have another try!
Mark
:I think I have the perfect solution:
:
: 0, 1, 2, infinite, -6, ....
:
: It is easy: 6/(3-n)
:
: Zara
:
:
: Juan Antonio Zaratiegui Vallecillo escribió:
: > Mark escribió:
: >> Like your thinking Zara but...
: >> ääääääääääää... <annoying game-show buzzing sound>
: >> ...not the answer I'm looking for.
: >>
: >> 1. The series is in base 10; so not 10, 11, 12...
: >>
: >> 2. I prepped Steve by mentioning his apparent bent for maths. It would
: >> be underhanded of me to then present a series that was
: >> alphabetically based. Also using "nul" (or "nil") instead of "zero"
: >> is not really playing fair; so not "nul, one, two, six, ten" (you
: >> forgot that one :-)
: >>
: >> 3. The fibonacci series extends to the left of zero as well as to the
: >> right, thus - ...5 -3 2 -1 1 0 1 1 2 3 5... For the '0' of my
: >> series to be generated in this manner requires a previous term
: >> of '0' and prior to that -1 and so on (see example below).
: >>
: >> "Mine": ...4 1 -2 0 -1 0 0 1 2 4 7 12...
: >> Fibon.: ...5 -3 2 -1 1 0 1 1 2 3 5 8...
: >>
: >> My series begins at '0', there are no previous terms that can
: >> exist. However, it is infinite and the fourth term is a little
: >> unexpected.
: >>
: >>
: >> Have another go.
: >>
: >> Mark
: >>
: >
: >
: > Another go:
: >
: > Series of primer numbers:
: > 1,2,3,5,7,11,13,17...
: > Mark series, 1 less:
: > 0,1,2,4,6,10,12,16...
: >
: > Do I get the cookie?
: >
: > Zara
: >
: >
: >
: > Yahoo! Groups Links
: >
: >
: >
: >
: >
: >
: >
:
:
:
:
: Yahoo! Groups Links
:
:
:
:
: